y^2+4y+32=0

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Solution for y^2+4y+32=0 equation:


Simplifying
y2 + 4y + 32 = 0

Reorder the terms:
32 + 4y + y2 = 0

Solving
32 + 4y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-32' to each side of the equation.
32 + 4y + -32 + y2 = 0 + -32

Reorder the terms:
32 + -32 + 4y + y2 = 0 + -32

Combine like terms: 32 + -32 = 0
0 + 4y + y2 = 0 + -32
4y + y2 = 0 + -32

Combine like terms: 0 + -32 = -32
4y + y2 = -32

The y term is 4y.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4y + 4 + y2 = -32 + 4

Reorder the terms:
4 + 4y + y2 = -32 + 4

Combine like terms: -32 + 4 = -28
4 + 4y + y2 = -28

Factor a perfect square on the left side:
(y + 2)(y + 2) = -28

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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